Matematika Sekolah Menengah Atas Q.

Beserta cara ya, terima kasih sebelumnya [tex]2 \sqrt{6} \times \sqrt{12} \div 3 \sqrt{8} [/tex]​

Q.

Beserta cara ya, terima kasih sebelumnya [tex]2 \sqrt{6} \times \sqrt{12} \div 3 \sqrt{8} [/tex]​

~Bentuk akar

[tex]= \sf{2 \sqrt{6} \times \sqrt{12} \div 3 \sqrt{8} }[/tex]

[tex]= \sf{(2 \sqrt{6} \times \sqrt{12} ) \div 3 \sqrt{8} }[/tex]

[tex]= \sf{ 2 \sqrt{72} \div 3 \sqrt{8} }[/tex]

[tex]= \sf{2 \sqrt{36 \times 2} \div 3 \sqrt{4 \times 2} }[/tex]

[tex]= \sf{2 \sqrt{ {6}^{\cancel{2}} \times 2} \div 3 \sqrt{ {2}^{\cancel{2}} \times 2} }[/tex]

[tex]= \sf{(2 \: . \: 6) \sqrt{2} \div (3 \: . \: 2) \sqrt{2} }[/tex]

[tex]= \sf{ 12 \sqrt{2} \div 6 \sqrt{2} }[/tex]

[tex]= \sf{ (12 \div 6)( \sqrt{2} \div \sqrt{2} )}[/tex]

[tex]= \sf{ 2}[/tex]

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